20c^2-17c-10=

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Solution for 20c^2-17c-10= equation:


Simplifying
20c2 + -17c + -10 = 0

Reorder the terms:
-10 + -17c + 20c2 = 0

Solving
-10 + -17c + 20c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-2 + -5c)(5 + -4c) = 0

Subproblem 1

Set the factor '(-2 + -5c)' equal to zero and attempt to solve: Simplifying -2 + -5c = 0 Solving -2 + -5c = 0 Move all terms containing c to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -5c = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -5c = 0 + 2 -5c = 0 + 2 Combine like terms: 0 + 2 = 2 -5c = 2 Divide each side by '-5'. c = -0.4 Simplifying c = -0.4

Subproblem 2

Set the factor '(5 + -4c)' equal to zero and attempt to solve: Simplifying 5 + -4c = 0 Solving 5 + -4c = 0 Move all terms containing c to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -4c = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -4c = 0 + -5 -4c = 0 + -5 Combine like terms: 0 + -5 = -5 -4c = -5 Divide each side by '-4'. c = 1.25 Simplifying c = 1.25

Solution

c = {-0.4, 1.25}

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